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I need help with the solving this problem! Can someone please give a detailed explanation on how to solve it?
8:08 Search MasteringChemistry <Chapter 16 Problem 16.81 < 9 of 12 > Review Constants Periodic Table Part A A solution of sod
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Soln Given pH = 9.48 So, pon= lymph = 14-9.48 = 41562 pon = 4.82 also we know that pos=-lag [ori] = 4.52= -log[Ort] [OH= 10 hК = [4 Сооп) Гонг 2 [ Сп, оо] 5. S X). (3.o2 хо) (9- 3.62 x).) (S.SS X) 0 - 15-20 х н — Ч. 1 2.0ч Хjo9 (5 сухо ° ) - 4, 12o

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