I need help on CHomework Answers
C6H5COOH + H2O <-------------> C6H5COO- + H3O+
part C) initially [C6H5COOH] = 0.054 M
from part A and B it is clear that
at equilibrium [H3O+] = [C6H5COO-] = 0.0018 M
amount of C6H5COoH dissociate = amount of H3O+ formed
means concentration of C6H5COOH dissocated = 0.0018 M
at equilibrium [C6H5COOH] = 0.054 - 0.0018 = 0.0522 M
answer = [C]HCOOH = 0.0522 M = 5.2 x 10-2 M
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I need help on C
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