Question

The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5.

Calculate the equilibrium concentration of H3O+ in the solution if the initial concentration of C6H5COOH is 0.065 M .

Express your answer using two significant figures.

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[H3O+] [ H 3 O + ] =		M

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Part B

Calculate the equilibrium concentration of C6H5COO− in the solution if the initial concentration of C6H5COOH is 0.065 M .

Express your answer using two significant figures.

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[C6H5COO−] [ C 6 H 5 C O O − ] =	nothing	M

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Answer 1

concentration of Benzoic acid (CgHCOOH) 0.065 M Ka of Benzoic acid 6.3 x 10-5 Let x be the change in the conc. of each species at equilibrium. К, Cан,соон + н,о М H,о* CSH5COO + Initial 0.065 0 0 Change -X X X Equillibrium 0.065 x х х.х 6.3x10- К, 0.065-x x26.3x104.095x106 = 0 by solving, we get x 0.001992 [H2O*] 0.001992M round to 2 sig.fig 0.0020M H,0'10.0020 M Part B [CH2COO0.0020 M X