Question

Part A Part complete Calculate [H3O+] in the following aqueous solution at 25 ∘C : [OH−]=...

Part A

Part complete

Calculate [H3O+] in the following aqueous solution at 25 ∘C : [OH−]= 5.3×10−4 M .

Express your answer using two significant figures.

--

SubmitPrevious AnswersRequest Answer

Part B

Part complete

Calculate [H3O+] in the following aqueous solution at 25 ∘C : [OH−]= 2.4×10−12 M .

Express your answer using two significant figures.

--

[H3O+]

[ H 3 O + ]

=

nothing

M

SubmitPrevious AnswersRequest Answer

Part C

Part complete

Calculate [H3O+] in the following aqueous solution at 25 ∘C : [OH−]= 2.2×10−2 M .

Express your answer using two significant figures.

--

[H3O+]

[ H 3 O + ]

=

nothing

M

SubmitPrevious AnswersRequest Answer

Part D

Part complete

Classify the solutions as acidic or basic.

Drag the appropriate items to their respective bins.

--

[H3O+]

[ H 3 O + ]

=

nothing

M

Reset

Help

  • [OH−]= 5.3×10−4 M

    [ O H Superscript-] = 5.3 times 10 Superscript -4 ~ M

  • [OH−]=2.2×10−2 M

    [ O H Superscript-] = 2.2 times 10 Superscript -2 ~ M

  • [OH−]=2.4×10−12 M

    [ O H Superscript-] = 2.4 times 10 Superscript -12 ~ M

  • Acidic solution

  • Basic solution

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A) The concentration of H3O + is calculated:

[H3O +] = 10 ^ -14 / [OH-] = 10 ^ -14 / 5.3x10 ^ -4 = 1.89x10 ^ -11 M

B) The concentration of H3O + is calculated:

[H3O +] = 10 ^ -14 / [OH-] = 10 ^ -14 / 2.4x10 ^ -12 = 4.17x10 ^ -3 M

C) The concentration of H3O + is calculated:

[H3O +] = 10 ^ -14 / [OH-] = 10 ^ -14 / 2.2x10 ^ -2 = 4.55x10 ^ -13 M

D) To:

[OH-] = 5.3x10 ^ -4 M

Basic solution

[OH-] = 2.2x10 ^ -2 M

Basic solution

[OH-] = 2.4x10 ^ -12 M

Acid solution

If you liked the answer, please rate it in a positive way, you would help me a lot, thank you.

Add a comment
Know the answer?
Add Answer to:
Part A Part complete Calculate [H3O+] in the following aqueous solution at 25 ∘C : [OH−]=...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Calculate [H3O+] given [OH-] in each aqueous solution. part A) [OH-] = 3.2x10^-12 M part B)...

    Calculate [H3O+] given [OH-] in each aqueous solution. part A) [OH-] = 3.2x10^-12 M part B) classify this solution as acidic or basic ^ part C) [OH-] = 3.0x10^-2 M part D) classify this solution as acidic or basic ^ part E) [OH-] = 1.6x10^-10 M part F) classify this solution as acidic or basic ^ part G) [OH-] = 1.8x10^-4 M part H) classify this solution as acidic or basic ^ Sign in MyLab & Mastering <Chapter 14 HW...

  • Calculate [H3O+] given [OH-] in each aqueous solution. view images for the 4 part question <Chapter...

    Calculate [H3O+] given [OH-] in each aqueous solution. view images for the 4 part question <Chapter 14 Hw Exercise 14.65 with eText link Calculate H,O* given [OH in each aqueous solution Part E OH-1.6x10-10M Express your answer using two significant figures. VOAXD ? м H,O] Request Answer Submit Part F Classity this solution as acidic or basic. acidic basic Bequest Answer Submit Part G (он -18104 М neyueai MIIDnel Submit Part G (OH-18x10-4 M Express your answer using two significant...

  • In Review Calculate (H3O+] in the following aqueous solution at 25 °C: [OH-] = 1.1x10-9M. Express...

    In Review Calculate (H3O+] in the following aqueous solution at 25 °C: [OH-] = 1.1x10-9M. Express your answer using two significant figures. VO AL ? [H3O+]= M Submit Request Answer Part B Calculate (H3O+] in the following aqueous solution at 25 °C: (OH-] = 2.9x10-2M. Express your answer using two significant figures. ΠΗ ΑΣΦ ? [H,0*] = M Submit Request Answer Pearson

  • Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 1.0×10−9 M . Calculate [H3O+]...

    Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 1.0×10−9 M . Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 2.3×10−2 M . Calculate [H3O+] in the following aqueous solution at 25 ∘C: [OH−]= 6.1×10−12 M . Classify the solutions as acidic or basic. [OH−]=1.0×10−9 M[OH−]=1.0×10−9 M [OH−]=2.3×10−2 M[OH−]=2.3×10−2 M [OH−]=6.1×10−12 M[OH−]=6.1×10−12 M

  • Calculate [H3O+] given [OH−] in each aqueous solution. Part A [OH−] = 6.6×10−11 M Part B...

    Calculate [H3O+] given [OH−] in each aqueous solution. Part A [OH−] = 6.6×10−11 M Part B Classify this solution as acidic or basic. Part C [OH−] = 4.5×10−9 M Part D Classify this solution as acidic or basic. Part E [OH−] = 6.6×10−4 M Part F Classify this solution as acidic or basic. Part G [OH−] = 2.5×10−2 M Part H Classify this solution as acidic or basic.

  • Calculate the [H3O+] of each aqueous solution with the following [OH-]: 19 of 20 Part A...

    Calculate the [H3O+] of each aqueous solution with the following [OH-]: 19 of 20 Part A 0 of each aqueous solution OH stomach acid, 1.7 x 10-13 M Express your answer to two significant figures and include the appropriate units. alue Units Submit Request Answer vPart B urine, 3.8 x 109 M Express your answer to two significant figures and include the appropriate units. Value Units Submit Request Answer Part C orange juice, 2.7 x 1011 M Express your answer...

  • calculate the [H3O+] of each aqueous solution with the following [OH-]: Part C cleanser, 3.0x10-5 M....

    calculate the [H3O+] of each aqueous solution with the following [OH-]: Part C cleanser, 3.0x10-5 M. Express your answer using two significant figures. | ΑΣΦ 6 ? [H30*) = M Submit Request Answer Part lemon juice, 3.5x10-13 M. Express your answer using two significant figures. IVO AXO ? [H,0')- M Submit Request Answer

  • Calculate the pH to the correct number of significant figures for solutions with the following concentrations...

    Calculate the pH to the correct number of significant figures for solutions with the following concentrations of H3O+ or OH? . Part A Part complete [H3O+] = 2.5×10?5 M SubmitPrevious AnswersRequest Answer Part B Part complete [OH?] = 10?3 M pH = SubmitPrevious AnswersRequest Answer Part C Part complete [H3O+] = 3.50×10?9 M pH = SubmitPrevious AnswersRequest Answer Part D Part complete [H3O+] = 9×10?3 M pH = SubmitPrevious AnswersRequest Answer Part E Part complete [OH?] = 15 M pH...

  • The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+...

    The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the solution if the initial concentration of C6H5COOH is 0.065 M . Express your answer using two significant figures. TemplatesSymbols undoredoresetkeyboard shortcutshelp [H3O+] [ H 3 O + ] =   M   SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 5 attempts remaining Part B Calculate the equilibrium concentration of C6H5COO− in the solution if the initial concentration of C6H5COOH is 0.065 M . Express your answer...

  • Describe how to prepare each solution from the dry solute and the solvent. Part A Part...

    Describe how to prepare each solution from the dry solute and the solvent. Part A Part complete How much dry solute would you take to prepare 135 mL of 0.100 M NaNO3 ? Express your answer using three significant figures. -- Part B Part complete How much dry solute would you take to prepare123 g of 0.120 m NaNO3 ? Express your answer using three significant figures. -- msolute m s o l u t e = nothing gNaNO3 Part...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT