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Part A Determine the molecular formula of a compound that is 49.48% carbon, 5.19% hydrogen, 28.85% nitrogen, and 16.48% oxyge
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Solution : Let the molecular formula of Compound is Cp Hq Ny Os % Carbon (1. c) = Px Atomic X 100 Molecular wei of compound w% of oxygen SX Atomic wei weight of oxygen Molecular weight of compound X loo w 16.48 = coot SX 16 X 100 194.19 ( S = 16.48 x

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Part A Determine the molecular formula of a compound that is 49.48% carbon, 5.19% hydrogen, 28.85%...
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