Question

Solve the following equations:

(a) 5x + 2 = 7 (b)

6x + 5 = 3x + 11

(c) 2x - (1-3x) = 8x - 2(3x - 4)

Answer 1

(a) Curen can : 5x + 2 = 7. To elinunate 2 from 2.H.S , we add (-2) to both sides of the ear. 50+2 +(-2) = 7+ (-2). or 50+ 2-2 = 7-2 or 5n = 5 Now to get the value of an, we multiply the egn with (1/5) - $(5) $ (5) or x = 1 Thus the solution is a 21 Ans (6) 6a +5 = 3a + 1 To solue for a, we have to arrange the egn so that the a terms be at L.its and the constant terms at the R. His of the eau Thus we add (-30-5) to both sides of the eq? 62 +5+ (-3x - 5) = 34+11 + (-3x - 5) o bx+ /-3x - 4 = 34+11 - 8x - 5 or 3x = 6 Now we multiply both sides of the ear with (1/3)

. $ (34) = (6) on as 2 Thus the solution is: x=2. x=2. An (e) 2x - (1-3) = 8x-2 (3-4) 2x-1 +3x = 8x - 6x + 8 50-1 a 20 + 8 0 we add t2m+1) to both sides of the egne .: 5a - 1 + (-2x +1) = 2a +8 +(-22+1) on Ja-x-20+1 = 20 + 8 - 2x+1 on 3x = 9 Now, we multiply both sides of the ear with : (3m) - (9) on x 23 Thus the solution is : a = 3 Auz