Question

.-21 2. (a) +5 represents the position of a body moving in a line, with s in meters and t in seconds with 1 St 54. (5 Marks) a) Find the body's displacement for the given interval. b) Find the body's speed and acceleration at the end points of the interval. c) Find the body's acceleration when the velocity is zero. d) Find the body's speed when the acceleration is zero.

Answer 1

4 represents the position of a moving body aline with Si meter und in 4 borlys Jisplacement 1 5 Sei). 4. 4 1 35 meter 1 4- 2. - 2 13 2.1 is velocity and 4 t ds dit 44 4 time t is accelonation of any time t d's dit 34 4 at ds ch 113-4.11 = 3. m/s t=4 48 m/s at speed = 164-16 | 43-4:41 ds dt le=41 is — at Accelaration 2. 2 3.1 -4 = -1 mis at t = 4 is m đi Aceloration 2 d's T12 t=4 44 3:42-4= ds Zeyo = 0 When velocrly is Тc cTt +-4 t = 0 t(t-4) but t=-2 is it -0,2,-2 not physical . -4 not valid to is not belong to ist<+) is then occcloration at t=u d's as 2, acccluration leco ho are long at t=2 2. 8 m/s² 3.2² 1) data Hence d's dila CScanned with CamScanner 8 lecz m/s²

. When "Ze YO accclaration is dis die 3t? - 4 o but is not valid as 2 t J3 trepresents time Hence = 1155 which lies in زرين " ist 54 time interval Hence 2 4 53 141.31-14-40).a.al -16) e 15) - (sus mifoliant 8 353 53 = 16 353 d. 9 t = wte CScanned with CamScanner