Question

8) During a collision with a wall,the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from the wall. If the time the ball was in contact with the wall was 60.0 ms, what was the magnitude of the average force applied to the ball? A) 26.7 N B) 13.3 N C) 107N D) 40.0 N E) 16.7 N
10) A 5.0-m radius playground merry-go-round with a moment of inertia of 2000 kg.m2 is rotating freely with an angular speed of 1.0 rad/s. Two people, each having a mass of 60 kg, are standing right outside the edge of the merry-go-round and step on it with negligible speed. What is the angular speed of the merry-go-round right after the two people have stepped on? A) 0.80 rad/s B) 0.20 rad/s C) 0.40 rad/s D) 0.60 rad/s E) 0.67 rad/s
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Answer #1

Q1.

Ans-   (a) 26.7 N

Force applied is , F= change in momentum of ball / time duration

F= (mVf - m Vi)/ t

F= (0.200*12 - 0.200*20)/(60.0 * 10^-3)

F= - 26.7N

Hence magnitude of force applied is 26.7N.

So, correct option is (a) 26.7 N

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