Question

QUES TON 8 A BAR WITH A DIMETER LENGTH ROUND OF OF 820 ma 3a mm S SuBJECTED TO A TENSILE FOECE OF 52, 332 kN NHICH INCEEASES ITS LENG TH By 0,621 mm CALCLATE THE TOHLOWING 8.1.1 THE STEESS /N THE BAR 812 THE STznIN .1-3 YOUNG 'S mobuLus OF ELASTICITY OF THE MATELIML OF THE PRE 8-2 A CtGE IS LoNERED NIT H A DIAMETER OF 5mm LENGTH By 8 mm MASS OF 1,8 TONS bowN A StteFT ByAWiRE ND A F 5om 7 HE WIRE STRETCHES WITH A YouNG'S MobulUS FoR THE DE TCRMINE MATERIML OF THE WIRE

engineering science

Answer 1

shape - Round Dia D :- 32 mm = 32 x 10 m Length, L :- 820mm = 820 x 10 m Tensile force, P = 52.332 KN - = 52 332 N SL= 0.621 mm = 0.621 x 10 m 8.1.1 :- stress 6 = P A 6.365.069504 16 = 65.069504 MPa MPa Ans- 8.1.2 :- strain :- Oh = change in length original length = 17.57317 x 10-47 No unit Ans. E = 0.621 820

8.1.3 Young's Modulus of Elasticity E = 6 = 65.069504 E 7.57317 x 10-4 E = 85.921 x 103 MPa Ans. 8.27 Mass = 1.8 tons Weight = 1.8 x 1000 x kq 9. 81 - 17658 N = 5mm = (5x10-3 m. ID IL =50 m; SL = 8 x 10 m НЕ S=PL OR E = PL AD E = 17658 x 50 #x(5x10 32 x 8x10 3 4

E = 5.620716 8 10 12 = 5.620716 10. lor ma E = 5.6.20716 x 10 5 MPa