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Determine the equivalent stiffness in the following systems: 20 kg E - 200 x 10 m2 I-1.15 x 10 m Massless beam TE TI E. wi TI
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1. Kim Amos E- 200% 109N) m2 I 1.158104me ok 20kg I. и Deflection @ midspan. Simply supported beam :- Deflection 3 Ss PL p=20The equivalent stiffum of the beam and in uf spoing 8o. keq, k of BEI _3 upperspring] and ( beams. Jare in And. The Lower sprPotential energy VE { keq x² 23 115 -43 >7 he TE 80. V= \ 3K42 +4 * (8) Let. My cu. Q Then NI +/- 2 ng 43 к (. 45 - 11.196 9НАМ - 2013 ki 93- ч, -Ч. 5 XL Кем —yvүм- Е, go. Из * * * j = Зур. Also. з, 19 у И, З ч. 4 Чs 8 प. 11 ку. Ча . у Ча соо 2 уу,

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