Question

A pole leans away from the sun at an angle of 5° to the vertical. When the elevation of the sun is 55°, the pole casts a shadow 47 ft long on level ground. How long is the pole? ft long. The pole is (Round to the nearest foot as needed.)

Answer 1

Shadow leaning Pole -- leane by h leane by 47 47 BC = length of shadow = 47ft LA BC = 90° - leaning angle LABC = 90°-5° = 85° - 4 LAB C = 850] LACB = 550) ... ( given) sums of angles of triangle is 180° LABET LBCAT LCAB = 180° 85 + $5° + LCAB = 180° LC AB = 180 - 140 L CAB= 40. By sine Rule 47 АВ sinsso sin 40° AB - 47 x sin55° sin 40° TAB = 59.89559) is a length of pole

hearst foot - 100 ft nearst