A ball is thrown horizontally from a height of 17.1 m and hits the ground with a speed that is three times its initial speed. What was the initial speed?
from kinematic equation
v2 - u2 = 2as
(3u)2 - u2 = 2 * 9.8 *17.1
2 u2 =335.16
u=12.94 m/s
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