Question

Question 6 of 8 > Complete and balance the given precipitation reactions, including the physical states of the products as predicted by the solubility rules. AgNO3(aq) + NaBr(aq) — K,PO, (aq) + MgCl, (aq) → Examine the precipitation reactions to determine whether each of the involved species is oxidized, reduced, or neither. Oxidized Reduced Neither A 1153 PM des

Answer 1

Solution 0 AgNO3(aq) + NaBrags -> Ag Bas) + NaNO3(aq) © 2K3 Pou (69+3Mg Cez (aq) = 6 klag) + Mg 3(PO4)2(5) Both reactions are the example of double displacement action as we know that double displacment reactions are non redox reactions so we can say that in both double displacement precipitation reaction all involved species are neither oxidized nor reduced. oxidized Reduced Neither Agt, Na, Kt, No5, Mg2+ Br, pour ce showing oxidation states of all metal and nonmetal in reactiaction 1. The same will happen in reaction 2 SPOScanned with CamScanner

Ag NO3 (all) + NaBrave -> Ag Br (s) + Na Noz (au) oxidation number of Ag in AgNO3 oxidation number of Ag + El) = 0 oxidation number of Ag = +1. oxidation number of Ay in Ag Br oxidation number of Ag + oxidatiotion number of Bx = 0 oxidation number of Ag + C) = 0 O.N. of Ag = +1 No change in oxidation number of Ag so it is neither oxidized nos reduced. oxidation number (ON.) of NOx in AgNO3 = -1 CON.of Ag = +1) O.N. of Nog in NaNO3 = -1 (O.N. of Nau+i) No change in oxidation number can.) of NOZ so it is neither oxidized nos seduced. * On.of Na in NaBr = + (ON. of Br = -1). O.N. of Na in NaNO3 = + (O.N. of NO3 = -1) There is no change in oxidation number of Nat so it is neither oxidized note reduced. The O.N. of Br in NaBr = -1 D.No of Br in Agonca Co.N. of Ag= +1) No change in O.N. of Br so it is neither oxidized nor reduced. ned with CamScans