Question

< Question 8 of 13 > A beaker containing a solution of HCl is shown. Which NaOH solution will just neutralize the HCl solution in the beaker? about us | Careers | privacy policy terms of use contact us help

Answer 1

Hee is a strong acid so it remains in dissociated form in water ine, it and coo when we add aoH to tre solution- there is formation of tho and Nace. Now H2O is a weak aid to dissociate info Ht and on, so it remains as H2O. But Nace enest as wat and ci in solution. Thus if uce were previously there there upon addition of NaOH There will be uce and unat Hot ce NaoH tot ce e +40 H₂O H₂O Na Na Natal H2O H₂O thol the nt ce cu a- ca a hoce Ht ut ce H₂ H30 solution has to so, becomes H2O(A) Thus the correct represent is option (2) 8-molecules of tho and u molecule of Na+ and u molecules of ce-

This is the correct representation.