Question

Tipler6 26.P.024. A 12 cm length of wire carries a current of 4.5 A in the positive z direction. The force on this wire due to a magnetic field B is f - (0.2 i + 0.2 J) N. If this wire is rotated so that the current flows in the positive x direction, the force on the wire is f 0.2 kN. Find the magnetic field B Ti Submit You currently have 3 submissions for this question. Only 5 submission are allowed You can make 2 more submissions for this question Your submissions: 222 j Computed value: .222 Feedback: ). Submitted: Monday, April 23 at 6:24 PM 2) 20/12 You currently have 2 submissions for this question. Only 5 submission are allowed You can make 3 more submissions for this question TJ Submit Your submissions: 20/12 x Computed value: 1.66666666666667 Feedback: Submitted: Monday, April 23 at 6:22 PM 3) TK Submit You currently have 1 submissions for this question. Only 5 submission are allowed You can make 4 more submissions for this question Your submissions: 0 Computed value: 0 Feedback: Submitted: Monday, April 23 at 6:20 PM

Answer 1

The magnetic force acting on the current carrying wire in the magnetic field is ILB sin θ Here, Γ is the current in the wire. L is the length of the wire, B is the strength of the magnetic field, and θ is the angle between wire and magnetic field The force is, f-(4.5 A) (12x10 m)kx(Bi+B,j+BA) -(4.5 A) 0 0 12x102 B. B a(4.SA)[(-12x10-2%)i-(-12 x 10-2 B.)+0] =-54x 10-B,i + 54 × 10-2B.j Comparing, 0.2i +0.2j--54x10 B,i+54x10-Bj The components of field are 0.2 T 0.0037 T *54 0.2 T 54 0.0037 T