Page |62 ADDITIONAL or OPTIONAL QUESTIONS 4. A 150.0 g sample of aluminum, c 0.90 J(gxoC),...

Question

Question

Answer 1

Answer #1

Heat lose of Al = Heat gain of water

mc $\Delta$ T = mc $\Delta$ T

150*0.9*(250-t) = 100*4.18*(t-22)

t = 77.66⁰C

The fonal temperature = 77.66⁰C >>>>answer

Answer 2

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