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Example 1: Using the data from Communities 1 and 2 above and calculate Simpsons Index For Community 1: 18 of 20 individuals are Species A So for Species A. (pi)2 (18/20)2-0.81 I of 20 individuals are Species B For Species B, (pi)2 (1/20)2-0.025 l of 20 individuals are species C For Species C. (pi)2-(1/2°)2 0.025 Y (pi)2 0.815 Simpsons Index is 1-0.815, or 0.185 for Community 1 For Community 2: D-1-[(7/20)2+ (8/20)2+(5/20)2] Simpsons Index-1-0.1225+0.16+0.0625] Simpsons Index-l-[0.345] 0.655 So Community 2 has a higher biodiversity. Now, compare the diversity of these two kinds of mixed nuts using Simpsons Index: Species Number in “Mixed Nuts Number in Deluxe Mixed Nuts Brazil nut Cashew 15 Almond Peanut 15 85 18 We will set up a table to record the calculations: Species Number in(P Species Number in Deluxe (pF Brazil nut Cashew Pecan Mixed Nuts Mixed Nuts Brazil nut 15 Pecan 15 18 Peanut 85 Peanut 0 Total Total Mixed Nuts. ? (pi)2 and 1-?(pi)2 ? (pi)2- and 1- (pi)2 Deluxe Mixed Nuts: 1. Which of the populations of nuts has the higher biodiversity? 2. Count the number of individuals of each species, and enter your data in the tables for each forest patch, listing each species and the number of occurrences of the species in the collection

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