Question

What output is produced by the following code? Explain how it works.

1.1 1 ...2..... 5 package taesik; import java.util.; /* Your name: Date: Answer: How it works: */ class student String name; int age; 1 public class Quiz21 ( public static void main(String args[])! ArrayList<student>myArray = new ArrayListo(); for(int i=0; i< 6; i++) { student s = new student(); s.name="Emily" ; 3.ageri; myArray.add(s); 1 for (int i = 0; i <myarray.size(); i++) { System.out.format($s $den", myArray.get(i).name, myArray.get(i)-age); } System.out.println(); for (int i = 0; i<myArray.size(); i++) myArray.remove(i); System.out.format("%s %d %n", myArray.get(i).name, myArray.get(i).ago); - 1

Answer 1

Output:

Emily 0
Emily 1
Emily 2
Emily 3
Emily 4
Emily 5

Emily 1
Emily 3
Emily 5

Explanation:

• ArrayList<student>myArray=new ArrayList<>();
         for(int i=0;i<6;i++)
         {
             student s = new student();
             s.name="Emily";
             s.age=i;
             myArray.add(s);
         }

This part of code will create an ArrayList names myArray which stores objects of type student. And the loop will create 6 student objects. In those objects, in all objects the name will be "Emily" and age will be 0,1,2,3,4,5 respectively. In the last part of this code, the created objects will be added into ArrayList myArray which is created before.

• for(int i=0;i<myArray.size();i++)
         {
             System.out.format("%s %d %n",myArray.get(i).name,myArray.get(i).age);
         }

This Part of code will display names and ages in the objects which are stored in myArray.

i.e.,

Emily 0

Emily 1

Emily 2

Emily 3

Emily 4

  Emily 5

• for(int i=0;i<myArray.size();i++)

       {
           myArray.remove(i);
           System.out.format("%s %d %n",myArray.get(i).name,myArray.get(i).age);
}

In this loop, first, it is removing the object that is stored at index respective to the value of i. And then it;s displaying the name and age that are stored in the ith object in ArrayList.

If we remove student object at 0th index, the objects after index 0 will be shifted left. That means object at index 1 will move to index 0. That's why we are only getting

Emily 1

Emily 3

Emily 5