Question

9.2 Let ,, , xn be iid n(θ, 1). A 95% confidence interval for θ is 쪼± 1.96/Vn. Let p denote the probability that an additional independent observation, Xn+1, will fall in this interval. Is p greater than, less than, or equal to .95? Prove your answer.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given data

X1 -----------Xn be iid N (0.1)A 95% confidence interval for x bar positive negative 1.96 √A. Let P denote the probability that an additional independent observation. it would be less than 0.95. it is because that the given confidence interval is for theta. Which is the population mean. It shows that is is 95% chance that population mean will lie in this interval.

The next additional independent observation will belong to population distribution not to random sampling distribution.

ad ditional nde ndn ogevatio xyrt → 1↓ would be les llano.qs. T is because Iddhe given confidence inlenvab isfon thia cD) ohich s Jhe Pofulation, mton mea n ol le in this intenvel The nextad indefcndent obsenavdlier zuill belons oouioiution not lo sundm Sampling d istoi bution Jam ete by allachirs PoPulation and sample 91a Pofuktion mab olie on po distai butions and the Jiven conlidence inkcal Jst dells us thet hPopulalion mean ill ie. Butte next obsevation ie as re oPulation distaibution, which oill susnely te Jess than 95%

Add a comment
Know the answer?
Add Answer to:
9.2 Let ,, , xn be iid n(θ, 1). A 95% confidence interval for θ is...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT