First question not clearly visible please re-post again
2)
Binomial probability
P(X = r) = nCr * P^r * q^n-r
Given n = 7, p = 0.65 and q = 1-p = 1-0.65 = 0.35
a)
P(X = 2) = 7C2 * 0.65^2 * 0.35^5 = 7!/2!(7−2)! * 0.4225 * 0.0053
P(X = 2) = 0.04660
b)
P(X ≤1) = P(X = 0) + P(X = 1)
P(X = 0) = 7C0 * 0.65^0 * 0.35^7 = 7!/0!(7−0)! * 1 * 0.00064 = 0.00064
P(X = 1) = 7C1 * 0.65^1 * 0.35^6 = 7!/1!(7−1)! * 0.65 * 0.0018 = 0.0084
P(X ≤1) = 0.00064 + 0.0084 = 0.0090
c)
P(X > 5) = P(X = 6)+P(X = 7)
P(X = 6) = 7C6 * 0.65^6 * 0.35^1 = 7!/6!(7−6)! * 0.0754 * 0.35 = 0.1848
P(X = 7) = 7C7 * 0.65^7 * 0.35^0 = 7!/7!(7−7)! * 0.0490 * 1 = 0.0490
P(X > 5) = 0.2338
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