Question

A disk has 20 surfaces (i.e. 10 double sided platters). Each surface has 1000 tracks. Each...

A disk has 20 surfaces (i.e. 10 double sided platters). Each surface has 1000 tracks. Each tracks has 128 sectors. Each sector can hold 64 bytes. The disk space allocation policy allocates an integral number of contiguous cylinders to each file,

a.) How many bytes are contained in one cylinder?

b.) How many cylinders are needed to accommodate a 5-Megabyte file on the disk?

c.) How much space is wasted in allocating this 5-Megabyte file?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

To know that A cylendar has 15 tracks;

as per the given question 1 Track = 128 sectors
1 sector= 64 bytes
so,

1) 1 cylender= 15tracks
= 15*128*64 =122880 bytes or 122.88kb

2) for 5MB file to be recorded on a disk around 42 cylendars to be required

Expl: 1024*5--->?

122.88-->1 cyleendar

= 1024*5/122.88 = 41.6


3) so Wasted space is 322 bytes

Add a comment
Know the answer?
Add Answer to:
A disk has 20 surfaces (i.e. 10 double sided platters). Each surface has 1000 tracks. Each...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 12 Consider a magnetic disk drive with 10 double sided platters, 512(=2^9) tracks per surface,...

    Question 12 Consider a magnetic disk drive with 10 double sided platters, 512(=2^9) tracks per surface, and 1024 (=2^10) sectors per track. Sector size is 2KBytes (=2^10 Bytes ). Assume the average seek time 0.02 ms, the seek time from a track to its adjacent track can be ignored. The drive rotates at 5400 rpm. Successive tracks in a cylinder can be read without head movement. Furthermore, disks can be handled independently, so multiple tracks in a cylinder can be...

  • A typical hard drive consists of 4 platters. For each platter is single sided. Each surface...

    A typical hard drive consists of 4 platters. For each platter is single sided. Each surface consists of 4096 tracks, each divided into 256 sectors. Each sector can hold 1024 bytes of data. The platters rotate at a speed of 14,400 rpm. The track to track arm movement time is 0.002ms.   Show your work. What is the maximum amount of data that can be stored on the entire drive, including all platters and sides? Express your answer both in bytes...

  • Question 7. A hard disk has the following parameters 8 surfaces 40,000 tracks per surface •...

    Question 7. A hard disk has the following parameters 8 surfaces 40,000 tracks per surface • 512 sectors per track 1024 bytes per sector Rotational speed 10,000 rpm a) What is the capacity of the drive? b) What is the rotational latency? c) Once a sector has been accessed, what is the rate at which data is read?

  • Problem 8, chapter 11-I/O Management And Disk Scheduling, Stalling Operating system

    Calculate how much disk space (in sectors, tracks, and surfaces) will be requiredto store 300,000 120-byte logical records if the disk is fixed-sector with 512bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces.Ignore any file header record(s) and track indexes, and assume that records cannotspan two sectors.---------------------------------------------------------------------------------------------------P4Consider the disk system described in Problem 3, and assume that the disk rotatesat 360 rpm. A processor reads one sector from the disk using interrupt-driven I/O,with one interrupt per byte....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT