Question

Calculate how much disk space (in sectors, tracks, and surfaces) will be required
to store 300,000 120-byte logical records if the disk is fixed-sector with 512
bytes/sector, with 96 sectors/track, 110 tracks per surface, and 8 usable surfaces.
Ignore any file header record(s) and track indexes, and assume that records cannot
span two sectors.
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P4
Consider the disk system described in Problem 3, and assume that the disk rotates
at 360 rpm. A processor reads one sector from the disk using interrupt-driven I/O,
with one interrupt per byte. If it takes 2.5 µs to process each interrupt, what
percentage of the time will the processor spend handling I/O (disregard seek
time)?


I know the answer to p3 >> i want the answer to p4 , thanks

Answer 1

Consider the following information:

Number of bytes/sector=512

Size of each logical record=120 bytes

Number of records =300,000

Thus, the number of logical records that each sector can hold

Number of records per sector=4

Number of sectors in 300,000 records=75,000

Number of sectors per track=96

Number of tracks in 300,000 records=782

Number of tracks per surface=110