Question

Ni(OH)2 ksp = 2.8x10^-16

Solid sodium hydroxide is slowly added to 50.0 mL of a 0.0501 M nickel(II) nitrate solution. The concentration of hydroxide ion required to just initiate precipitation is M Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

The concentration of the hydroxide ion required to just initiate precipitation is 1.069 * 10^—3 M.

The detail calculation is shown below.

Nickel (11) nitrate dissociates to soom Ni2e and 2 Noz. Ni(NO3)2 = Ni2+ + 2N05 The moparity of the Ni (NO3), solution is 0.050 M. Thus [ Ni2e] = 0.0501 M. Naot is slowly added to 50 ml of a 0.0501 M Ni (NO3)2 solntion to form precipitation of Ni (OH)2 Ni (OH)2 ? Ni 2+ + 204. i keq = [Ni2+] [ OH]? [Ni(OH)₂] e. Ksp = [Ni24] [or] 2 Kap of Ni (OH)2 = 2.8x1016. us consider the concentration of - is a. .: Ksp = [Ni 2+] [ 2x]2 - 4.20.0504 = 2.8x106.

x = 2.8x10-16 400.050 - s = 1.069 *10^3 m. . The concentration of hydroxide ion required to just initiate the precipitation is 1.069 4103 M.