Question

Matlab problem

A vector, x, containing values between 0 and 5 is generated randomly below. % the length of x is also determined at random. % set up a "for" loop to run over all elements of x - use the "length" command % inside the "for" loop, use a "switch" construct to find the odd values % and the even values (including zero) - use two "case" commands inside the "case" for the odd values, use an "if" so that if a 3 % or a 5 is found, that value is replaced by its square - leave any 1's unchanged inside the "case" for the even values, use an "if" so that if a 4 % is found, that value is replaced by its square root - leave any 0's % or 2's unchanged. % % So, 1's, 0's, and 2's will stay the same. 3's and 5's will be replaced % by their square. 4's will be replaced by their square root. % % Example output for x before (top row) and after (bottom row) running % through the "for" "switch" and "if" constructs % % 5 3012400 1 3 % 25 9012200 1 9 % f print f('\n\n#2\n') clear all x=round(5*rand(1, 5+round(5*rand))); disp(x); % your code goes here % Given -disp(x) %

Answer 1

Here is the code for you:

fprintf('\n\n#2\n');

clear all

%A vector x, containing valuews between 0 and 5 is generated randomly.

%The length of x is also dtermined at random.

x = round(5*rand(1, 5+round(5*rand)));

disp(x);

%Set up a for loop to run over all elements of x.

for i = 1 : length(x)

%Inside the for loop use a switch construct to find the odd values:

switch(mod(x(i), 2))

case 1

%Inside the case for the odd values, use an if so that if a 3,

%or 5 is found, that value is replaced by its square.

if x(i) == 3 || x(i) == 5

x(i) = x(i) * x(i);

end

case 0

%Inside the case for even values, use an if so that a 4 is

%found, that value is replaced by its square root.

if x(i) == 4

x(i) = sqrt(4);

end

end

end

disp(x);

And the output screenshot is:

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