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1. (a) We need to calculate accurate values of the function for very large values of x. However, it is found that just progra

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Answer #1

IF YOU HAVE ANY DOUBTS COMMENT BELOW I WILL BE TTHERE TO HELP YOU..ALL THE BEST..

AS FOR GIVEN DATA.

The term \sqrt{x^2+3}-\sqrt{x^2+2} is the main reason for such poor accuracy because if x is large then \sqrt{x^2+3} and \sqrt{x^2+2} both are large too and subtraction of such a large numbers doesn't make sense. This is the same thing as \infty -\infty. However if we follow the steps :

f(x)=x^2\left[ \sqrt{x^2+3}-\sqrt{x^2+2}\right ]

f (x)

f (x)-

f(x)=\frac{x^2\left[x^2+3-x^2-2\right ]}{\left[ \sqrt{x^2+3}+\sqrt{x^2+2}\right ]}

f(x) =

This is the form where we can get more accurate value than the previous one.

I HOPE YOU UNDERSTAND..

PLS RATE THUMBS UP..ITS HELPS ME ALOT..

THANK YOU...!

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