Homework Answers
`Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
This is happening because when matlab is trying to evaluate the 5+exp(x) as a part of calculation it identifies it as beyond calculation for x=720 but exp(-720) is a number which can be calculated by matlab.So, function gives inf. But, when x=750 both becomes inf and 0. So, inf*0 became an NaN.
So, to have it corrected. h(x) is (5+exp(x))*(exp(-3*x)+exp(-x))
So, expand it, h(x)=5*exp(-x) + exp(-2*x) + 5*exp(-3*x) + 1
So, now below matlab program will run fine
clc
clear all
x=[1,10,100,400,720,750];
h=@(x) 5*exp(-x) + exp(-2*x) + 5*exp(-3*x) + 1;
[x' h(x')]
Kindly revert for any queries
Thanks.
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for small or moderately small values of x. this is a special
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special function called the exponential integral. it rises in
diffraction problems.
Derive a Taylor-series expression for f(x), and give an upper
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