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(20 pts) Consider the circuit below. Assume the operating frequency of 60 Hz. m j1.92 12 -j2 A © 3 4.8 <1.61, 380 (a) (10 pts

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Answer #1

Given circuit; Apply KCL at Nude 1 31.921 in 4.8 & 8n 1-6 In V 4.8 = vir V2 11-92 j 4 V+ ViVe j2 =j2 j1.92 » V. (1+34) V₂ = -

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