A pharmaceutical company wants to answer the question of whether it takes longer than 45 seconds for a drug in pill form to dissolve in the gastric juices of the stomach. A sample was taken from patients taken the given drug in pill form and times for the pills to be dissolved were measured as the following
42.7 , 43.7 , 44.6 , 45.1 , 45.6 , 45.9, 46.8 , 47.6
A. State the hypotheses to test this question
B. State the Assumption of the test.
C. Perform the test and determine if it's statistically significant at a=0.05
D. Interpret the result.
Here, we have to use one sample t test for the population mean.
Part A
The null and alternative hypotheses are given as below:
H0: µ = 45 versus Ha: µ > 45
This is an upper tailed test.
Part B
We assume that the sample data is from normally distributed population.
Part C
The test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
From given data, we have
µ = 45
Xbar = 45.25
S = 1.595529469
n = 8
df = n – 1 = 7
α = 0.05
Critical value = 1.8946
(by using t-table or excel)
t = (Xbar - µ)/[S/sqrt(n)]
t = (45.25 – 45)/[ 1.595529469/sqrt(8)]
t = 0.4432
P-value = 0.3355
(by using t-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
Part D
There is not sufficient evidence to conclude that it takes longer than 45 seconds for a drug in pill form to dissolve in the gastric juices of the stomach.
A pharmaceutical company wants to answer the question of whether it takes longer than 45 seconds...
A pharmaceutical company wants to answer the question whether it takes longer than 45 seconds for a drug in pill form to dissolve in the gastric juices of the stomach. A sample was taken from 18 patients who were given drug in pill form and times for the pills to be dissolved were measured. The mean was 45.212 sec for the sample data with a standard ERROR of 0.580. Determine the P-value for this test.