Suppose sin(a)= - 3 5 with 180°<a <270°, what is cos(2a)? 24 25 7 25 7...
7. Given cos 20 = --and 180° <0 < 270°, find values of sino and cose.
3 Given sin osesan and sin B -7 37 25 <B< 27. Find cos(0 + B).
Suppose 0 is in the interval 90° <O< 180°. Find the sign of the following. cos (0 + 90°) Choose whether the sign of cos (0+ 90°) is positive or negative. Negative Positive
Find the following tan . given sin o = -, 180° <0<270 (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)
If csc(I) = 6, for 90° <I< 180°, then Preview sin() = 0 cos(1) Preview tan (3) - Preview
Suppose sin 0 - 5 and 0<o<". Determine sin(20). DO NOT use a calculator
Draw the following graph on the interval – 180° < x < 270°: y = sin(x + 60°) 2 1 -150 -120 -90 -60 -30 30 60 90 120 150 180 210 240 N 1. What is the amplitude of the function? 2. What is the period of the function?
Find the exact value of sinſ and cos given that cos x = 3,27 ,270° <x< 360°. [8] 4-cos e 18. cos20-5 cos 0+4 since 1+cos e
1. Use an identity to find the exact value of cos(?) given that cos(O) = { with 270° << 360°
Solve fort, 0 < t < 27. 32 sin(t)cos(t) = 12 sin(t)