Question

The radius of curvature of a spherical convex mirror is 20 cm. Describe the image formed when a 25-cm-tall object is positioned at the the following distances. For each case, provide the image distance, the image height, the type of image (real or virtual), and the orientation of the image (upright or inverted)

(a) 5 cm from the mirror

dI = ______ cm

hI = ______ cm

The image is virtual and inverted?

The image is virtual and upright?

The image is real and upright?

The image is real and inverted?

(b) 20 cm from the mirror

dI = _____ cm

hI =______ cm

The image is virtual and inverted?

The image is virtual and upright?

The image is real and upright?

The image is real and inverted?

(c) 100 cm from the mirror.

dI =______ cm

hI = ______ cm

The image is virtual and inverted?

The image is virtual and upright?

The image is real and upright?

The image is real and inverted?

Answer 1

Raditus of curvature of the convex lens is, R- 20 cm Hence the focal length of the lens is, R 20 cm f- -10 cm Object height, h, -25 cm

(a) Object distance, d.- 5 cm Using the lens formula, do d, f d f do (10 cm) (5 cm) 10 cm d,-10 cnm Using the formula for magnification, 10 cm) 5 cmm d, h doh -d, ho( - (-10 cm)(25 cm ) 5 cm h, -50 cm In this case the image is virtual and upright

(b) Object distance, d 20 cm Using the lens formula, do d, .f d f do (10 cm) (20 cm) 20 cm d,-20 cm Using the formula for magnification, d, h do ho -d, -(20 cm) (25 am) (20 cm h,25 cnm In this case the image is real and inverted

(c) Object distance, d。= 100 cm Using the lens formula, do d, f d f do (10 cm) (100 cm) 100 cm d,-11.11 cm Using the formula for magnification, d, h do ho 11.11 cm) (25 cm (100 cm) -d h,-2.77cm In this case the image is real and inverted.