you dissolve 0.125 g of this sultry aromatic compound in 25.0 g of chloroform, you discover...
you dissolve 0.125 g of this sultry aromatic compound in 25.0 g of chloroform, you discover that the solution boils at 61.82oC. What is the molar mass of this quixotic compound? (FYI: chloroform’s normal BP is 61.70oC; kb = 3.63oC/m)
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you dissolve 0.125 g of this sultry aromatic compound in 25.0 g
of chloroform, you discover...
Please show detail of all steps 6. You dissolve 0.89 g of an organic alcohol into...
Please show detail of all steps
6. You dissolve 0.89 g of an organic alcohol into 93.5 g of deionized water to make an aqueous solution. The solution boils at a temperature of 100.32 °C. Use this data to ealeulate the molar mass (g/mol) of the acid. Also state two actions you could take to raise the boiling point even higher and explain each decision briefly. Hint: work backwards from AT5 to find mol solute... Continue your work onto the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to
produce 25.0 mL of solution. The pH of this solution of HA(aq) is
1.33. We titrate this solution with a 0.250 M solution of NaOH. It
takes 41.9 mL of the NaOH solution to reach the equivalence
point.
(a) (2 points) What is the molar mass of HA?
(b) (2 points) What is the pKa value of HA(aq)?
(c) (2 points) What is the pH at the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.1 mL of the NaOH solution to reach the equivalence point.What is the molar mass of HA and What is the pKa value of HA(aq)?
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 44.5 mL of the NaOH solution to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the pKa value of HA(aq)? (c) What is the pH at the equivalence point? (d) What is the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.8 mL of the NaOH solution to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the pKa value of HA(aq)? (c) What is the pH at the equivalence point? (d) What is the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.6 mL of the NaOH solution to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the pKa value of HA(aq)? (c) What is the pH at the equivalence point? (d) What is the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 41.4 mL of the NaOH solution to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the pKa value of HA(aq)? (c) What is the pH at the equivalence point? (d) What is the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 43.3 mL of the NaOH solution to reach the equivalence point. (a)What is the molar mass of HA? (b)What is the pKa value of HA(aq)? (c)What is the pH at the equivalence point? (d) What is the pH one third...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL...
We dissolve 2.77 g of an unknown acid, HA, in enough water to produce 25.0 mL of solution. The pH of this solution of HA(aq) is 1.33. We titrate this solution with a 0.250 M solution of NaOH. It takes 40.2 mL of the NaOH solution to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the pKa value of HA(aq)? (c) What is the pH at the equivalence point? (d) What is the...
1) if 6.85 of glucose( C6H12O6, molar mass=180.2 g/mol) is dissolved in 155g of chloroform( CHCL3,molar...
1) if 6.85 of glucose( C6H12O6, molar mass=180.2 g/mol) is dissolved in 155g of chloroform( CHCL3,molar mass= 119.4 g/mol) , what is the boiling point of the solution. ( the boiling point of pure CHCl3 is 61.2 celsius, and Kb = 3.63 celsius/m for CHCl3) 2) a,) Liquid ammonia (boiling point = -33.4C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat 25.0 g of NH3(l) from -65.0C to -12.0C? Heat of...
Please show detail of all steps
6. You dissolve 0.89 g of an organic alcohol into 93.5 g of deionized water to make an aqueous solution. The solution boils at a temperature of 100.32 °C. Use this data to ealeulate the molar mass (g/mol) of the acid. Also state two actions you could take to raise the boiling point even higher and explain each decision briefly. Hint: work backwards from AT5 to find mol solute... Continue your work onto the...
We dissolve 2.77 g of an unknown acid, HA, in enough water to
produce 25.0 mL of solution. The pH of this solution of HA(aq) is
1.33. We titrate this solution with a 0.250 M solution of NaOH. It
takes 41.9 mL of the NaOH solution to reach the equivalence
point.
(a) (2 points) What is the molar mass of HA?
(b) (2 points) What is the pKa value of HA(aq)?
(c) (2 points) What is the pH at the...
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