Question

A wire with a current of 2.7A is at an angle of 37.0? relative to a magnetic field of 0.89T .

Find the force exerted on a 2.30?m length of the wire.

Answer 1

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A wire with a current of 2.7A is at an angle of 37.0? relative to a magnetic field of 0.88T .

Part A

Find the force exerted on a 2.35?m length of the wire.

Answer

F = ILxB

= ILBsin(37)

= 2.7*2.35*0.88*sin(37 deg)

= 3.36 N

Answer 2

Force acting on the wire=BILsin(angle).
Here, B=0.89T,

I=2.7A,

angle=37,

L=2.30m.
Substituting values, F=2.76345N

Answer 3

Force acting on the wire=B*I*L*sin(angle) Here, B-0.89T I-2.7A angle-37 L-2.3m F 0.89*2.7*2.3 *sin(37) F 3.326N