Question

I need a matlab code for given question. Please send matlab code sctript.

Question 1) (60 p) Consider following equation: axt-bx'+ex=dx-e Find the value of x via; a) Fixed Point iteration method with an accuracy of 0.0004 and a starting value of 1. b) Newton's Method with an accuracy of 0.0004 and a starting value of 1. Write the codes and the results to your paper.

a:2

b:3:

c:4

d:2.1

e:3.1

Answer 1

(a)
function[r]=fixed(x0,g,tol,n)
x(1)=x0;
for k=1:n
   x(k+1)=g(x(k));
   err=abs(x(k+1)-x(k));
   if(err<tol)
       break;
   end
end
r=x(k+1);

Above is the matlab code for fixed point iteration method. As per the question, x0=1 and tol=0.0004.

(b)

function[r]=newton(x0,f,df,tol,n)
x(1)=x0;
j=@(x) f(x)/df(x);
for k=1:n
   x(k+1)=x(k)-j(x(k));
   err=abs(x(k+1)-x(k));
   if(err<tol)
       break;
   end
end
c=x(k+1);

Above is the matlab code for newton's method. As per the question, x0=1 and tol=0.0004. df is the first derivative of the function.