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mmHg) Temp (oC) Temp (K) 1/Temp (Kt) 27.00 14313631640.0032 36bXIo 94.00 q3 123825.003 35xo 388.00 | 2, 53883172.1 60.00 1 3 33. 2 3.00x10-10 2b) Using the CHEMPLOT (or Excel) program, plot log(VP) versus 1/Temp. 2c) Write down the slope of the straight line your graph from CHEMPLOT (or Excel) gives you. (Make sure to use scientific notation and the correct units.) Slope 2d) Using the value you obtained for the slope, calculate the molar heat of vaporization, ΔHvap. (Make sure to use scientific notation and the correct units.) [Hint: ΔHva,--(slope)x(2.303)x(R)] their proper symbols, but the correct units on the slope, then write the complete equation for that line. 2e) From the equation of your CHEM PLOT (or Excel) graph, change、x andy to Equation:
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Answer #1

2)

slope = -4037.7

Ea/R = -slope

Ea = 8.314*4037.7 = 33569.43J/mol

Ea = 33.569 kJ/mol

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