Question

KG Q6A.15 Homework. Unanswered o Fill in the Blanks Determine the reactant acting as the reducing and oxidizing agents for the following reactions: C(s) + O2(g) + CO2(g) oxidizing agent 0 reducing agent O CH10(g) + O2(g) + CO2(g) +H20(g) oxidizing agent O reducing agent Unanswered . 2 attempts left Submit Try it

Answer 1

• Oxidising agent removes electron from other reactant.
• Reducing agent losses the electron to the other reactant.
• Oxidation: Loss of electrons is known as oxidation.
• Reduction: Gain of electrons is known as reduction.

1. C + O₂$\rightarrow$ CO₂

Here C has oxidation number 0 in reactant and +4 [x + 2(-2) = 0 ; x = +4] in product (CO₂).

So it means carbon is loosing electrons which means it is undergoing oxidation.

We conclude O₂ is Oxidising agent and CARBON is Reducing agent.

2. C₄H₁₀ + O₂$\rightarrow$ CO₂ + H₂O

Carbon has oxidation number -2.5 in C₄H₁₀ and +4 in CO₂.

So it means carbon has lost electrons and has undergone oxidation.

O₂ is Oxidising agent and C₄H₁₀ is Reducing agent.