Report the value of Kp for the decomposition of ammonium carbonate at 25°C if the total pressure of the system was 0.116 atm.
(NH4)2CO3 (s) ------------------------------> 2 NH3 (g) + CO2 (g) + H2O(g)
2x x x
total pressure = 2x + x + x = 4x
4x = 0.116
x = 0.029
Kp = PNH3^2 x PH2O x PCO2
Kp = (2x)^2 X (x) X (x)
Kp = 4 x^4
Kp = 4 x (0.029)^4
Kp = 2.83 x 10^-6
Report the value of Kp for the decomposition of ammonium carbonate at 25°C if the total...
Ammonium carbonate decomposes upon heating according to the following balanced equation: (NH4)2CO3(s)→2NH3(g)+CO2(g)+H2O(g) Calculate the total volume of gas produced at 24.0 ∘C and 1.01 atm by the complete decomposition of 11.8 g of ammonium carbonate.
I don’t understand
how the decomposition of ammonium carbonate works. Thanks .
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Solid ammonium carbonate, (NH4)2CO3, decomposes to produce NH3 and CO2 gases and water vapor according to the following equation: (NH4)2CO3 (s) «2NH3 (g) + CO2 (g) + H2O (g) A certain amount of solid ammonium carbonate, (NH4)2CO3, was placed in an evacuated and sealed 5,00-L flask and heated to 673 K. Some of the solid decomposed until equilibrium according to the above equation. Write an expression for the equilibrium constant kp for this reaction in terms of partial pressures, If...
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