Ammonium iodide, a solid, decomposes to give NH3(g) and HI(g). At 406 °C, some NH4I(s) is...
Ammonium iodide, a solid, decomposes to give
NH3(g) and HI(g). At
406 °C, some NH4I(s)
is placed in an evacuated container. A portion of it decomposes,
and the total pressure at equilibrium is 1.08 atm.
Extra NH3(g) is then injected into the
container, and when equilibrium is reestablished, the partial
pressure of NH3(g) is
1.27 atm.
(a) Compute the equilibrium constant in terms of pressures,
Kp, for the decomposition of ammonium
iodide at 406 °C.
NH4I(s) -->NH3(g) + HI(g) K =
(b) Determine the final partial pressure of HI(g)
in the container.
PHI = atm
Homework Answers
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Ammonium iodide, a solid, decomposes to give
NH3(g) and HI(g). At
406 °C, some NH4I(s)
is...
The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g)+ HI(g) NH4I(s) at 400...
The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g)+ HI(g) NH4I(s) at 400 °C is 4.65. (a) If the partial pressure of ammonia is PNH, 0.881 atm and solid ammonium iodide is present, what is the equilibrium partial pressure of hydrogen iodide at 400 °C? PHI atm (b) An excess of solid NH,I is added to a container filled with NH3 at 400 °C and a pressure of 1.17 atm. Calculate the pressures of NH(g) and HI(g)...
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I(s) + NH3(g) + HI(g) A. B. At 400°C,...
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I(s) + NH3(g) + HI(g) A. B. At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C. 0.103 atm 0.215 atm 0.232 atm 0.464 atm 2.00 atm The reaction system C. D. 32. POCI(o) + POCI(g) + Cl2(g)
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NHI(s) + NH3(g) + HI(g) At...
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NHI(s) + NH3(g) + HI(g) At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C. 0.103 atm 0.215 atm 0.232 atm 0.464 atm 2.00 atm E.
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1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <----> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.00 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2. The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K: NH4I(s) <----> NH3(g) + HI(g) Calculate the equilibrium partial pressure of HI when...
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At high temperatures, solid ammonium chloride decomposes into gaseous ammonia and hydrogen chloride. NH4Cl (s) ⇌ NH3 (g) + HCl (g) a) An excess of ammonium chloride was introduced into an evacuated container. After raising the temperature to 340 ° C, the pressure was measured 1.013 bar. Calculate the equilibrium constant at this temperature. (4p) b) A container of volume 1.00 dm3 initially contained 0.0200 moles of ammonia. What are the partial pressures for ammonia and hydrogen chloride after an...
Ammonium hydrogen sulfide decomposes according to the following reaction, for which Kp = 0.11 at 250°C:...
Ammonium hydrogen sulfide decomposes according to the following reaction, for which Kp = 0.11 at 250°C: NH4HS(s) ⇌ H2S(g) + NH3(g) If 52.5 g of NH4HS(s) is placed in a sealed 5.0−L container, what is the partial pressure of NH3(g) at equilibrium? PNH3 = atm ?
The equilibrium constant, K, for the following reaction is 9.25×10-3 at 692 K. NH4I(s) NH3(g) +...
The equilibrium constant, K, for the following reaction is 9.25×10-3 at 692 K. NH4I(s) NH3(g) + HI(g) An equilibrium mixture in a 12.1 L container at 692 K contains 0.348 mol NH4I(s), 0.118 M NH3 and 7.84×10-2 M HI. What will be the concentrations of the two gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 5.98 L? [NH3] = M [HI] = M
The equilibrium constant, K, for the following reaction is 6.76×10-3 at 685 K. NH4I(s) NH3(g) +...
The equilibrium constant, K, for the following reaction is 6.76×10-3 at 685 K. NH4I(s) NH3(g) + HI(g) An equilibrium mixture in a 11.7 L container at 685 K contains 0.229 mol NH4I(s), 0.101 M NH3 and 6.69×10-2 M HI. What will be the concentrations of the two gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 6.27 L?
Enter your answer in the provided box. Ammonium hydrogen sulfide decomposes according to the following reaction,...
Enter your answer in the provided box. Ammonium hydrogen sulfide decomposes according to the following reaction, for which Kp = 0.11 at 250°C: NH4HS(S) = H2S(g) + NH3(g) If 53.1 g of NH4HS() is placed in a sealed 5.0-L container, what is the partial pressure of NH3(g) at equilibrium? Рун, = atm
The equilibrium constant in terms of pressures, Kp, for the reaction NH3(g)+ HI(g) NH4I(s) at 400 °C is 4.65. (a) If the partial pressure of ammonia is PNH, 0.881 atm and solid ammonium iodide is present, what is the equilibrium partial pressure of hydrogen iodide at 400 °C? PHI atm (b) An excess of solid NH,I is added to a container filled with NH3 at 400 °C and a pressure of 1.17 atm. Calculate the pressures of NH(g) and HI(g)...
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I(s) + NH3(g) + HI(g) A. B. At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C. 0.103 atm 0.215 atm 0.232 atm 0.464 atm 2.00 atm The reaction system C. D. 32. POCI(o) + POCI(g) + Cl2(g)
31. Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NHI(s) + NH3(g) + HI(g) At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C. 0.103 atm 0.215 atm 0.232 atm 0.464 atm 2.00 atm E.
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