1.) O(n)
time taken: 0 sec.
memory: 1.47 MB
2.) O(n^2)
time taken: 0 sec
memory: 1.4 MB
3.) O(n^3)
time taken: 0 sec
memory: 1.3 MB
4.) O(n)
time taken: 0.6 sec
memory: 1.470496 MB
5.) O(n^2)
time taken: 0.54 sec
memory: 1.470496 MB
6.) O(2^n)
time taken: 0 sec
memory: 1.470496 MB
7.) O(n^4)
time taken: 0 sec
memory: 1.470496 MB
For each of the following six program fragments: a. Give an analysis of the running time...
4. Big-Oh and Rune time Analysis: describe the worst case running time of the following pseudocode functions in Big-Oh notation in terms of the variable n. howing your work is not required (although showing work may allow some partial t in the case your answer is wrong-don't spend a lot of time showing your work.). You MUST choose your answer from the following (not given in any particular order), each of which could be re-used (could be the answer for...
8. R-4.8 Order the following functions by asymptotic growth rate. 4nlogn + 2n 2^10 2^logn 3n + 100logn 4n 2^n n^2 + 10n n^3 nlogn 9. R-4.9 Give a big-Oh characterization, in terms of n, of the running time of the example 1 method shown in Code Fragment 4.12. 10. R-4.10 Give a big-Oh characterization, in terms of n, of the running time of the example 2 method shown in Code Fragment 4.12. 11. R-4.11 Give a big-Oh characterization, in...
In Big-Θ notation, analyze the running time of the following pieces of code/pseudo-code. Describe the running time as a function of the input size (here, n) for(int i=n-1; i >=0; i--){ for(int k=0; k < i*n; k++){ // do something that takes O(1) time } }
Give a big-Oh characterization, in terms of n,of the running time for each of the following code segments (use the drop-down): - public void func1(int n) { A. @(1). for (int i = n; i > 0; i--) { System.out.println(i); B. follogn). for (int j = 0; j <i; j++) System.out.println(j); c.e(n). System.out.println("Goodbye!"); D.@(nlogn). E.e(n). F.ein). public void func2 (int n) { for (int m=1; m <= n; m++) { system.out.println (m); i = n; while (i >0){ system.out.println(i); i...
Exercises • Determine running time for the following code fragments: (a) a = b + c; d = a + e; (b) sum = 0; for (i=0; i<3; i++) for (j=0; j<n; j++) sum++; (c) sum=0; for (i=0; i<n<n; i++) sum++; (d) for (i=0; i < n-1; i++) for (j=i+1; j <n; j++) { tmp = A[i][j]; A[i][j] = A[j] [i]; A[j][i] = tmp; (e) sum = 0; for (i=1; i<=n; i++) for (j=1; j<=n; j+=2) sum++;
1.4.6 Give the order of growth (as a function of n) of the running times of each of the following code fragments: a, int sum=0; for (int k n: k > 0; k /= 2) for (int i 0; ǐ < k; İ++) sum++; b.int sum 0; for (int i = 1; i < n; i *= 2) for (int j = 0; j < i; j++) sum++; int sum = 0; for (int í = 1; i < n;...
Q-1: Given the following code fragment, what is its Big-O running time? test = 0 for i in range(n): for j in range(n): test= test + i *j Q-2: Given3 the following code fragment what is its Big-O running time? for i in range(n): test=test+1 for j in range(n): test= test - 2 Q-3: Given the following code fragment what is its Big-O running time? i = n while i > 0: k=2+2 i...
Question 1 (25 pts) Find the running time complexity for the following code fragments. Express your answers using either the Big-O or Big-Θ notations, and the tightest bound possible. Justify your answers. for(int count O , i -0; i < n* n; i++) for(int i0 ; j <i; j++) count++ for(int count O , i -0; i
Hello, I would like to get help with the following algorithms and their respective analysis of runtime along with their recurrence equations, thanks in advance. 1. Analyze each of the following algorithms by providing a tight big-Oh bound on the run time with respect to the value n. Create a recurrence equation. a. void padawan(int n) { if( n <= 10 ) time++; else { for(int i=0; i<n; i++) time++; padawan(n/3); padawan(n/3); padawan(n/3); } } b. void nerfHerder(int n)...
***Please give comments and show it running*** Create a MIPS program that gets a set of numbers from the user, sorts them using selection sort, and displays the sorted numbers on the screen. You should create a subprogram to do the selection sort, sending it the length and address of the array. This is the pseudo code for the structure the selection: for (int i = 0; i < aLength-1; i++) { /* find the min element in the...