Following the give steps lets first find out the function as
The given integral is
so,
Plug these values in the equation of tangent
we have
Hence,
T3-EOY-MAT70 10- Choose the correct answer Hint on steps to follow: Find f'(x) or df/dx Then...
Assigned Each function f(x) changes value when x changes from Xo to xo + dx. Find the change Af = f(xo + dx) – f(xo), the value of the estimate df = f'(xo) dx, and the approximate error Af-df| f(x) = 4x2 - 5x, Xo = 2, dx = 0.1 The change Af=0. (Simplify your answer. Type an integer or a y=f Af = f + de) - doda of)) de Tangent о + de
The function f(x) changes value when x changes from xo to xo + dx. Find the change Af=f(xo + dx) = f(xo), the value of the estimate df = f'(x) dx, and the approximation error Af - dfſ. f(x) = 9x2 + 7%, * = 1, dx = 0.1 y = 0 T (T Af + d) - Mr) de ful Tangent 0 lue of Δf = (Type an integer or a decimal. Do not round.) df = 0 (Type...
At least one of the answers above is NOT correct. (1 point) Suppose f(x, t) = e 3t sin(x + 2t). (a) At any point (x, t), the differential is df = e^(-3t)cos(x+2t)dx+(e^(-3t))(2cos(x+2t)-2sin(x+2t))dt (b) At the point (-1,0), the differential is df = cos(-1)dx+(2cos(-1))+3sin(-1)dt (c) At the point (-1,0) with dx = -0.5 and dt = 0.3, the differential is df = 0.97344 Note. You can earn partial credit on this nrohlem (1 point) Consider the surface xyz = 20....
35. f(z) (3z+5)5 f(x) = SK-53 x-2 x2 -2x 37. f*)-+1 In problems 54-61, find dy/dx. 54. xy'- xy+10 0 In problems 62-63, find the equation of the tangent line to the given graph at the given point. 62. yxy - 6 0 at the point (1,2) 63. x+xy - vy-3 0 at the point (1,4) In problems 64-78, find y for the equation. 35. f(z) (3z+5)5 f(x) = SK-53 x-2 x2 -2x 37. f*)-+1 In problems 54-61, find dy/dx....
(3 points) The figure shows how a function f (x) and its linear approximation (.e., its tangent line) change value when I changes from co to co + dr. y = f(x) fredr) Suppose f(x) = x2 + 2x, xo = 2 and dr = 0.05. Your answers below need to be very precise, so use many decimal places. (a) Find the change Af = f (30+ dc) - f(:30). Af Error = 14f-df Af = f(x + dr) -...
PLEASE ANSWER #2 Problem 1: Find the general solution for dx d?.x dt2 + 2k- + k.x = 0 dt where k is an arbitrary constant. Problem 2: Find a differential equation with solution -2.x -23 y = e cos(x) +e sin(x). Hint: Use the property that i2 = = -1 to simplify your work.
consider the differential equation dy/dx = -2x/y. find the particular solution y = f(x) to the guven differential equation witht the intial condition f(1)= -1 umowed for this question. D Consider the differential equatio find the particular solution y = f(x) to the given differential equation with the initial condition f(1) = -1 46) = -1 Hy=f2 xdx 17 2 + C = -x +C (b) (9.6) be the region in the first quadrant bounded by the graph of y...
Problem 1: Find the general solution for dx d?.x dt2 + 2k- + k.x = 0 dt where k is an arbitrary constant. Problem 2: Find a differential equation with solution -2.x -23 y = e cos(x) +e sin(x). Hint: Use the property that i2 = = -1 to simplify your work.
L = sa V1 + [f'(x)]?dx = Se 1 + 2 dx dx Examples. Find the length of the arc of the following curves. y = Vx3 fromx = 1 to x = 4 2. y = {(x2 + 2) from x = 0 to x = 3 3. y=*+ from x = 1 to x = 3 (Ans:*) 2x 4. y + from x = 2 to x = 4 8x2 5. y = -x2 - In x from...
7. (10) If 1+ f(x) + x' [f(x)] = 0, and f(1) = 2, find f'(1). 8. (10) Differentiate the function 9. (10') Find an equation of the tangent line to the curve y=9-2x at the point (2,1) 7. (10) If 1+ f(x) + x' [f(x)] = 0, and f(1) = 2, find f'(1). 8. (10) Differentiate the function 9. (10') Find an equation of the tangent line to the curve y=9-2x at the point (2,1)