Question

Exit Full Screen code.cpp New 1 #include <iostream> 3 using namespace std; 4 5 int main) 6 int *ptr 7 ptr -new int[5]; 8 int arr[5]; 9int x; 10 cin >> x; 11 for( int í = 0; 1 < 5; 1++) // initialization 12 13 ptr[i] x; = 14 for O//your code goes here // your code goes here 16 for (int i=0; cout <<arri]; i < 5; i++) 17 20 delete ptr; 21 return0

I have to write a loop that moves the content of the dynamic array to the static array but I can't seem to figure it out.

Answer 1

Answer.) As requested in the question, providing the implementation of the for loop to move elements from dynamic to static array.

Code:

#include <iostream>

using namespace std;

int main()
{
int *ptr;
ptr = new int[5];
int arr[5];
int x;
cin>>x;
for(int i=0;i<5;i++) //initialization
{
ptr[i]=x;
}
//moving elements from dynamic to static array
for(int i=0;i<5;i++)
{
arr[i]=ptr[i];
}
for(int i=0;i<5;i++)//printing array
{
cout<<arr[i];
}
  
delete [] ptr;

return 0;
}

Output:

5                                                                                                                                                                                  

55555