Question

Part 1 In the network in the figure below, find RL for maximum power transfer and the maximum power transferred to this load. First find the Thevenin Equivalent Resistance. RTH the tolerance is +/-5% Click if you would like to Show Work for this question: Qpen Show Work ▼ Part 2 Next find the load resistance for maximum power transfer.

Answer 1

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for finding the Theorem equivalent resistance, we Reserve the current source This means that R_1, R_2and R_3 all in series with R_4 in parallel Therefore R_TH = (29 + 43 + 61) //73 R_TH = 47 . 5k - Fa max power transfer, Load resistance R_L = R_TH Therefore R_L = 47 . 5k -Fa finding V_TH, we notice that the current divides into 2 inches: R_1 + R_2 and R_3 + R_4 Thus, R = (R_1 + R_2) //(R_3 + R_4) = (29 + 43)//(61 + 74) = 47 k V = IR = 29 mA + 47 k = 94v Therefore V_Th = 94v - p_L = v_L^2/R_L where V_L = 94 times 47 . 5k/47 . 5 k + 47 . 5k = 47v Therefore P_L = 47 times 47/47 . 5 TildeEqualto 47w Therefore p = 47w

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