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A material is determined to have a wet unit weight of 115.0 pcf and a dry...
For a soil sample, the wet unit weight is 120 lb/ft3, and the moisture content is...
For a soil sample, the wet unit weight is 120 lb/ft3, and the moisture content is 20%. What is the dry unit weight of this soil sample? answer choices 120 lb/ft3 110 lb/ft3 105 lb/ft3 100 lb/ft3
A soil borrow material in its natural state in the ground has a unit weight of...
A soil borrow material in its natural state in the ground has a unit weight of 123 pcf. When a sample of this soil is dried in the laboratory, its dry unit weight is 103 pcf. What is the water content of this borrow material?
4. For the following laboratory data, calculate the weight of moist soil, moist unit weight, moisture...
4. For the following laboratory data, calculate the weight of moist soil, moist unit weight, moisture content and dry unit weight (fill in the blanks). (10) Test Volume of Mold, cubic feet Weight of mold, lbs Weight of Mold + Wet Soil, lb. Weight of Moist Soil, lb. Moist Unit Weight, lb/cubic foot Weight of Moisture Can, g Weight of Can + Wet Soil, g Weight of Can+Dry Soil, g Moisture Content, % Dry Unit Weight, lb/cubic foot | 0.0333...
A field unit weight determination test for the soil described in Problem 6.6 yielded the following...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
Air in a factory for drying apricots had dry bulb temperature of (Tdry) 25oC and wet...
Air in a factory for drying apricots had dry bulb temperature of (Tdry) 25oC and wet bulb temperature of (T wet) 15oC. What are the RH, dew point, Humidity ratio, specific volume and vapour pressure values. Second we are drying 10 Kg apricots of 85% moisture in batch production ending up with 60 % moisture content using a fan that blows hot air. We measured the air characteristics and found that Tdry = 35 oC and Twet=28 oC. The fan...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a Gs = 2.70. The moisture content and total density results are shown in the table below. Moisture Content 16% Wet unit weight (KN/m3) 19.1 18% 20.3 20% 20.7 22% 20.0 24% 18.2 a. Calculate the dry unit weight for each sample and type your answers in the first 5 answer boxes below (3 sigs, in KN/m3). b. Calculate the dry unit weight at zero...
Problem 1 Three samples of fine aggregate (FA) have the following properties Sample Measure Wet Mass (g) Dry Mass (g) Absorption (%) 622.6 591.7 620.9 593 620.0 592.6 2.6 2.52.2 Determine the fol...
Problem 1 Three samples of fine aggregate (FA) have the following properties Sample Measure Wet Mass (g) Dry Mass (g) Absorption (%) 622.6 591.7 620.9 593 620.0 592.6 2.6 2.52.2 Determine the following: a) Define the terms saturated surface dry (SSD) and free moisture. b) For the samples results from above compute the total moisture content for each sample batch and the average and standard deviation of the three samples. Free moisture content of the samples. c)
Problem 1 Three...
The bank material for constructing an embankment has a unit weight of 80 lbf/f3, water content...
The bank material for constructing an embankment has a unit weight of 80 lbf/f3, water content is 9%, specific gravity of solids is 2.78. The required fill material has a unit weight of 110 lbf/f3, the required moisture is 11%. Please calculate the bank volume to construct 678,566 yd3 embankment.
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
4. For the following laboratory data, calculate the weight of moist soil, moist unit weight, moisture content and dry unit weight (fill in the blanks). (10) Test Volume of Mold, cubic feet Weight of mold, lbs Weight of Mold + Wet Soil, lb. Weight of Moist Soil, lb. Moist Unit Weight, lb/cubic foot Weight of Moisture Can, g Weight of Can + Wet Soil, g Weight of Can+Dry Soil, g Moisture Content, % Dry Unit Weight, lb/cubic foot | 0.0333...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a Gs = 2.70. The moisture content and total density results are shown in the table below. Moisture Content 16% Wet unit weight (KN/m3) 19.1 18% 20.3 20% 20.7 22% 20.0 24% 18.2 a. Calculate the dry unit weight for each sample and type your answers in the first 5 answer boxes below (3 sigs, in KN/m3). b. Calculate the dry unit weight at zero...
Problem 1 Three samples of fine aggregate (FA) have the following properties Sample Measure Wet Mass (g) Dry Mass (g) Absorption (%) 622.6 591.7 620.9 593 620.0 592.6 2.6 2.52.2 Determine the following: a) Define the terms saturated surface dry (SSD) and free moisture. b) For the samples results from above compute the total moisture content for each sample batch and the average and standard deviation of the three samples. Free moisture content of the samples. c)
Problem 1 Three...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
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