1. How much energy is released when an ice cube tray containing 250 ml of water freezes? The heat of fusion for water is 6.02 kJ/mol.
density of water is 1 g/mL
volume = 250 mL
mass of water = density * volume
= 1 g/mL * 250 mL
= 250 g
molar mass of water = 18 g/mol
so,
mol of water = mass / molar mass
= 250 g / 18 g/mol
= 13.89 mol
Q = Hfus*number of mol
= 6.02 KJ/mol * 13.89 mol
= 83.6 KJ
Answer: 83.6 KJ
1. How much energy is released when an ice cube tray containing 250 ml of water...
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