Question

Suppose you put some water in your ice-cube tray and then place the tray in the freezer. Consider a single ice cube that starts out as 31.0 ml of liquid water at 20.0°C. To determine the energy that must be removed from the water to convert it to an ice cube, we must consider the process in three stages. For stage 1, determine how much energy must be removed from the water to cool it to water at 0.00°C Enter your answer as a negative value.

Answer 1

Total energy removed from water to converted ice at -10 degree

Total energy removed from water to converted ice at -10 degree For stage 1 Q_1 = mc increment T Q_1 = 31 times 10^-3 liter times 4200 J/kg k (0 degree - 20 degree) because 1 Liter = 2 kg hence Q_1 = 31 times 10^-3 times 4200 (-20) Q_1 = -2604 J For stage 2 Q_2 = mL = 31 times 10^-3 times 3.3 times 10^5 J/kg Q_2 = -10230 J Q_3 = mc increment T Q_3 = 31 times 10^-3 times 2108 J/kg c (-10 degree -0 degree) \r\n Q_3 = -653.48 J Total energy Q = Q_1 + Q_2 + Q_3 Q = -2604 - 10230 - 653.48 Q_T = -13487.5 J