Question

B 106° 120 100 feet feet 60° 599 C A 1350 106 86 feet feet The table below shows the field data for closed traverse ABCD, if
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Hi,

Step 1: Adjusting measured angles:

Observed Angle A = 59o

Observed Angle B = 106o

Observed Angle C =60o

Observed Angle D = 135o

Total                       = 360o

Theoretical sum of angles of ploygon= (n-2) x 180o (where n=number of sides)

Theoretical sum of angles of given quadrilateral = (4-2) x 180o =360o

Angular error = 360o-360o = 0

Hence the angles measured are correct and no correction is required in angles at this point.

Results are presented below:

Station

A

B

C

D

Observed Angle

59o

106o

60o

135o

Correction in each angle

0o

0o

0o

0o

Adjusted angle

59o

106o

60o

135o

Step 2: Calculation of azimuths of all lines

For a clockwise traverse, azimuth of other lines with one known azimuth is calculated by below formula:

Azimuth of preceding line = Azimuth of previous line - Angle between lines + 180o

Azimuth of AB                   =                             56o

Balance azimuths:

Azimuth of BC = 56o – 106o + 180o = 130o

Azimuth of CD = 130o – 60o + 180o = 250o

Azimuth of DA = 250o – 135o + 180o= 295o

Step 3: Calculating Northing and Easting of each line:

Formula:

Northing = Distance x cos (Azimuth)

Easting = Distance x sin (Azimuth)

Accordingly results are furnished in below table:

Line

Length

Azimuth

Northing

Easting

feet

feet

feet

AB

120

56o

67.1031

99.4845

BC

100

130o

-64.2788

76.6044

CD

106

250o

-36.2541

-99.6074

DA

86

295o

36.3452

-77.9425

Sum

412

2.9154

-1.4609

Step 4: Calculating Coordinates of each line:

Formula:

North Coordinate of an end = North coordinate of another end + Northing of line

East Coordinate of an end = East coordinate of another end + Easting of line

Accordingly results are furnished in below table:

Station

Line

Northing

Easting

Coordinates
(N-S)

Coordinates
E-W

A

0.0000 N

0.0000 E

AB

67.1031

99.4845

B

67.1031 N

99.4845 E

BC

-64.2788

76.6044

C

2.8244 N

176.0890 E

CD

-36.2541

-99.6074

D

-33.4297 N

76.4815 E

DA

36.3452

-77.9425

Step 5: Calculating corrected Northing and easting of each line:

As per Bowditch rule for a closed traverse:

Correction in northing of a line = total error in northing x length of line / perimeter of traverse

Correction in easting of a line = total error in easting x length of line / perimeter of traverse

Accordingly results are furnished in below table:

Line

Length

Northing

Easting

Correction in northing

Correction in easting

Adjusted Northing

Adjusted Easting

1

2

3

4

5

6

7 = 3-5

8=4-6

AB

120

67.1031

99.4845

0.8492

-0.4255

66.2540

99.9100

BC

100

-64.2788

76.6044

0.7076

-0.3546

-64.9864

76.9590

CD

106

-36.2541

-99.6074

0.7501

-0.3759

-37.0042

-99.2315

DA

86

36.3452

-77.9425

0.6086

-0.3050

35.7366

-77.6375

Sum

412

2.9154

-1.4609

2.9154

-1.4609

0.0000

0.0000

Step 6: Calculating final coordinates of each line:

Final Coordinates According to adjusted northing and easting are furnished in below table:

Station

Line

Northing

Easting

Coordinates
(N-S)

Coordinates
(E-W)

A

0.0000 N

0.0000 E

AB

66.2540

99.9100

B

66.2540 N

99.9100 E

BC

-64.9864

76.9590

C

1.2676 N

176.8691 E

CD

-37.0042

-99.2315

D

-35.7366 N

77.6375 E

DA

35.7366

-77.6375

a) Fill up the table:

Station

Observed Angle

Azimuth

Length

E

N

To Station

A

59o

56o

120

67.1031

99.4845

B

B

106o

130o

100

-64.2788

76.6044

C

C

60o

250o

106

-36.2541

-99.6074

D

D

135o

295o

86

36.3452

-77.9425

A

Sum

360o

412

2.9154

-1.4609

b) Calculate the corrected angles:

Station

A

B

C

D

Observed Angle

59o

106o

60o

135o

Adjusted angle

59o

106o

60o

135o

c) Find DE and DN

d) Find the closing error

Closing error = 3.2610 feet

e) Find the relative accuracy

Relative accuracy = 0.007915 = 1/126

f) Fill up the table

Station

Line

Corrected DN

Corrected DE

(N) Correct

(E) Correct

A

0.0000 N

0.0000 E

AB

0.8492

-0.4255

B

66.2540 N

99.9100 E

BC

0.7076

-0.3546

C

1.2676 N

176.8691 E

CD

0.7501

-0.3759

D

-35.7366 N

77.6375 E

DA

0.6086

-0.3050

Add a comment
Know the answer?
Add Answer to:
B 106° 120 100 feet feet 60° 599 C A 1350 106 86 feet feet The...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • PROBLEM 8. The following data has been taken and calculated for a 5-course loop traverse. CourseLength...

    PROBLEM 8. The following data has been taken and calculated for a 5-course loop traverse. CourseLength Latitude AB rture 1005 24 +335.34 395.75 +244.83 +436.84 870.53+775.38 1034.62 550.71 CD DE EA 1178.72 364 27 112102 1094.06 1092.65 -55.49 The coordinates of A are x 2000.00; y 1500.00. Sketch course AB. Correct the latitudes and departures of courses AB and BC with the compass rule and report the coordinates of station B. (15 points) PROBLEM 9. The following data has been...

  • 1)During a mountain climbing trip it is observed that the water used to cook a meal...

    1)During a mountain climbing trip it is observed that the water used to cook a meal boils at 93 °C rather than the standard 100 °C at sea level. At what altitude are the climbers preparing their meal? (See Physical Properties of Water (SI Units) and Properties of the U.S. Standard Atmosphere (SI Units) for data needed to solve this 2)The following bearings taken on a closed compass and fill up the table. Lines Bearings (deg-min) Azimuth N Deflection Angles...

  • 1) An observer fails to check the bubble of a level and it is off two...

    1) An observer fails to check the bubble of a level and it is off two divisions on a 100-m sight. If the sensitivity of the bubble is 20-sec, what error would there be in the reading? 2 ) The following azimuths are from the north: 329°20’, 180°35’, 48°32’, 170°30’, 145°25’, 319°35’, 350°45’, 95°49’, 11°30’, 235°45’. Express these directions as (a) azimuth from the south, (b) back azimuths, (c) bearings. 8) 6.7 The following azimuths are reckoned from the north:...

  • 1) An observer fails to check the bubble of a level and it is off two...

    1) An observer fails to check the bubble of a level and it is off two divisions on a 100-m sight. If the sensitivity of the bubble is 20-sec, what error would there be in the reading? 2 ) The following azimuths are from the north: 329°20’, 180°35’, 48°32’, 170°30’, 145°25’, 319°35’, 350°45’, 95°49’, 11°30’, 235°45’. Express these directions as (a) azimuth from the south, (b) back azimuths, (c) bearings. 8) 6.7 The following azimuths are reckoned from the north:...

  • N28°46'25" 87*14'32" 210-06-29 148*09'56" 54°42'10" 5442'10" Ta 208*49' 39" S30°45'33" E Bearing from 1 to 2...

    N28°46'25" 87*14'32" 210-06-29 148*09'56" 54°42'10" 5442'10" Ta 208*49' 39" S30°45'33" E Bearing from 1 to 2 Bearing From 2 to 3 Bearing from 3 to 4 Bearing from 4 to 5 Note: Use the carat^(shift+6) in place of the degree symbol because degree is not available on the keyboard. Question 1 8 pts How many meters and feet are in a mile? mile = meters (to the nearest.01 meters) mile = feet Question 2 16 pts Draw a sketch of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT