C) A merter stick pivoted at its center has a 150gm mass suspended at its 20cm mark. a) Where should an 100gm mass be placed to produce equilibrium? b) What mass placed at the 90cm mark is needed to produce equilibrium?
Please show work so I can understand
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
C) A merter stick pivoted at its center has a 150gm mass suspended at its 20cm...
2. A meter stick was pivoted at the 30 cm mark with its center of gravity at the 50 cm mark. If a mass of 25.29 g is hanging at the 70.35 cm mark, what mass must be hung from the 11.98 cm mark in order for the system to be in equilibrium? (Take the mass of the stick to be 98 g)
2. A meter stick was pivoted at the 30 cm mark with its center of gravity at the 50 cm mark. If a mass of 25.29 g is hanging at the 70.35 cm mark, what mass must be hung from the 11.98 cm mark in order for the system to be in equilibrium? (Take the mass of the stick to be 98 8)
Torques and Center of Mass. The
Experiment:
In this experiment, you balance a meter stick, to balance the
meter stick, attach masses at positions until the system is in
equilibrium.
The meter stick acts as if all its mass was concentrated at its
center of mass. With the fulcrum at the center of mass, r (the
distance from the axis of rotation to the place where the force is
applied) is 0, so there’s no torque due to the meter...
Suppose that a meter stick is balanced at its center. A 0.18 kg mass is then positioned at the 8-cm mark. At what cm mark must a 0.22 kg mass be placed to balance the 0.18 kg mass? Please help
A uniform meter stick (a ruler 100 cm long) is supported by a fulcrum at its 20 cm mark balances when a 200 g mass is suspended at the 0 cm end. Assume that the center of mass of the meter stick is exactly at its middle, the 50 cm mark. Determine the mass of the meter stick, in grams. Please show your work.
Consider a stick of length I, mass m, and uniform mass density. The stick is pivoted at its top end and swings around the vertical axis. Assume that conditions have been set up so that the stick always makes an angle with the vertical. a) Figure out what the principal axes are. You do not necessarily need to diagonalize the I 3. matrix. It will be obvious to find them. Calculate the diagonal components of the moment of inertia tensor....
A meter stick has a mass of 0.12 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 12.0 cm toward the end with the chain. Determine the mass of the chain.
A meter stick has a mass of 0.27 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 26.0 cm toward the end with the chain. Determine the mass of the chain.
the experimental part for this question is all answered there is
only the last part where it says:
Compute the net torque about 20 cm
mark.
Mass of the stick : 0.1383 kg
Compute the net torque about the end of the stick.
please be sure to put detailed answer for both parts 1 and 2
thanks for the help!
Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick...
A uniform wooden meter stick has a mass of m = 799 g. A clamp can be attached to the measuring stick at any point Palong the stick so that the stuck can rotate freely about point P, which is at a distance d from the zero-end of the stick as shown. Part (a) Calculate the moment of inertia in kg-m of the meter stick if the pivot point P is at the 50-cm mark. Part (b) Calculate the moment of inertia...