Suppose a meter stick. Now, its mass is concenterated on the 50 cm mark. Now, we know that it balances on 20 cm mark which is 30 cm to the left of central 50 cm mark.
Also, the 200 g mass is at 0 cm mark. which is 20 cm left to the fulcrum
Now, using definition of torque, we have
let x be the mass of the meter stick
200*20 = x * 30
x = 200*20 / 30
x = 133.33 gms
A uniform meter stick (a ruler 100 cm long) is supported by a fulcrum at its...
4. The meter stick balances at the 49.7 cm mark when placed on the fulcrum, the center of gravity of the meter stick is located 49.7cm from the zero end. The free-body diagram of the stick when it is balanced with the 50.0-g mass attached at the 10.0cm mark is as given below. Find the mass of meter stick, M. AR Point O - 39.2 cm - 10.0 cm (50.0 g)? 49.7 cm 49.7 cm Me
A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center of mass at the 50 cm mark). A 35 g mass is placed at the 10 cm mark. What mass would have to be placed at the 75 cm mark to balance the meter stick?
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
A uniform meter stick is supported on a knife edge at the 32.0 cm mark. When a 125 g mass is hung at the 16.0 cm mark, the stick is balanced. What is the mass of the meter stick?
the fulcrum is positioned at the 50cm mark on the meter stick. A 50g mass is hung from 67 m mark on the stick. Also a 200g mass is suspended from the 89 cm mark. A. Calculate the total clockwise torque due to these masses B. assuming that the total counterclockwise torque is equal to the answer in (A) above, calculate the position on the meter stick where 315g mass must be suspended in order to balance the stick.
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 56.5-gram mass is attached at the 17.0-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick?
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 65.0 gram mass is attached at the 17.5 cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick? Submit Answer
A uniform meter stick is balanced with the pivot located at the 60 cm mark. And a mass of 50 grams placed at the 85 cm mark. What is the mass of the meter stick?
A meter stick is found to balance at the 50.0 cm mark when placed on a fulcrum. When a 0.100 kg mass is attached at the 10.0 cm mark, the fulcrum must be move to the 34.0 cm mark for balance. a) What is the mass of the meter stick? b) How much torque does the 100 g mass exert on the meter stick around an axis at the new fulcrum (at 34.0 cm) c) How much torque does the...