A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center of mass at the 50 cm mark). A 35 g mass is placed at the 10 cm mark. What mass would have to be placed at the 75 cm mark to balance the meter stick?
Considering equilibrium of torque
hanging mass * distance from hinge = mass of meter * distance of COM from hinge + balncing mass * distance feom hinge
35* (40 - 10) = 10 * 50 + 35* m
m = 15.714 g
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A fulcrum is placed at the 40 cm mark on a 50 g meter stick (center...
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