Question

Calculate the equilibrium concentration of dissolved oxygen in 25°C water at sea level (p = 1.00 atm), and again at 4000 m elevation in 5°C water. [Use the exponential p vs. z equation provided in the lectures, not the empirical formula given in the textbook.]
$P(z)=P(O)exp(-z/H)$

Answer 1

This question is from dissolved oxygen concept.

I am giving the solution on paper.

& Solution, equilibrum concentration of dissolved oxygen T= 250 = 273k P=latm 40oom elevation in soc. P (2) = Plo) exp(-2/H) # Po = (M) RT C = Hoze Pog Hoo for oxygen at 298 k = 13x10 mol/l-atm Po2 = (2] RT (at Standard Conditions) = 0.0031 moll 4.0089 atm | mol-k X298k => 0 10 76 atm = 'C= 1.3 x10 mol x 0. 076 eftir 1C = 0.0988 X10 moi This is the dissolved oxygen concentration. L-atma