Question

60 MPa 45 MPa 70 120 MPa

a) Construct Mohr's Circle
b) Determine principal planes and principal stress
c) Determine maximum shearing stress
d) Determine normal stress and shear stress in C plane.

Answer 1

Solution (9) Mohr's Circle. Scale 120MPa = 8cm . GOMPa = 4cm. 45 MPa = 3cm TA 60,45) Imox 2 call C (120,45) = 2.4 cm 2.4x120=36 MPa 8 9.6cm = 9.6x120 = 144 MPa 8 Tmax = 3.6cm = 3.6x120 = 54 MPa. 8

Solution! – (6) & (C) (6) Principal planes & principal Stress Given x = 120 MPa Txy= 45 MPa y = 60MPa 2 x + y + ox + 2 2 Trey =(120460)+ ve -60)2 + 452 2 144 MPa. C2 = ( 120 + 60 (120-60 ) + 452 5) - (120 2 35.91 & 36 MPa. Shear Stress T maximum I-3 144-36 2 2 = 54 MPa Crincipal plames are at tanzo 2 Tay 2x45 120-60 = 1.5 Ix- og 20 = tan (1.5) x 180 28, 15° & O. 2 118.150 (602= 0, +90)

A * 120 mpa Solution (d) :- 20 10 C B 45 MPa GOMPa Taking o from Vertical plane - 98-70-20 Normal stress in C-plane (+)+1(2-69) cos 20 + Leysin 20 * (120*60) + 4 (120 - 6o) Cos (2x 20)+ 45 Sin (2x20) 103.52 MPa. Shear stress in a plane you sin 20+ T cos20 To (60*120) sin(2x20) + 45 Cos (2x20) - - 52.36 MPa. Tot 52.36 MPa.